If z=x+iy is a complex number which satisfy |z−5i||z+5i|=1, then z lies on
A
the real axis
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B
the straight line, y=5
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C
a circle passing through the origin
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D
the imaginary axis
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Solution
The correct option is A the real axis Given : |z−5i||z+5i|=1 ⇒|z−5i|=|z+5i| So, z is the perpendicular bisector of line segment joning (0,5) and (0,−5) Therefore, the locus of z is y=0 Which is x− axis.