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Question

Question 81 (ii)

Add :

9ax+3bycz,5by+ax+3cz

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Solution

We have,
(9ax+3bycz)+(5by+ax+3cz)
=9ax+3bycz5by+ax+3cz
=(9ax+ax)+(3by5by)+(cz+3cz) [grouping like terms]

=10ax2by+2cz


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