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Question 81 (i)

Add :

7a2bc,3abc2,3a2bc,2abc2


Solution

We have,
7a2bc+(3abc2)+3a2bc+2abc2=7a2bc3abc2+3a2bc+2abc2
=(7a2bc+3a2bc)+(3abc2+2abc2)         [grouping like terms]
=10a2bc+(abc2)
=10a2bcabc2

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