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Question

Question 81 (vii)

Add :

3a(2b+5c),3c(2a+2b)

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Solution

We have,
3a(2b+5c)+3c(2a+2b)
=(6ab+15ac)+(6ac+6bc)=6ab+15ac+6ac+6bc
[grouping like terms]
=6ab+21ac+6bc


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