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Question 22(ii)
An electron moving with a velocity of 5×104ms1 enters into a uniform electric field and acquires a uniform acceleration of 104ms2 n the direction of its initial motion.

(ii) How much distance the electron would cover in this time?

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Solution

Given initial velocity, u=5×104ms1 and acceleration, a=104ms2
(ii) Using s=ut+12at2
=(5×104)×5+12(104)×(5)2=25×104+252×104=37.5×104m

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