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Negatives and Reciprocals

ii Find the r...

Question

Question 86 (ii)

Find the reciprocal of the following:
$\frac{20}{51} \times \frac{4}{91}$

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Solution

Given, $\frac{20}{51} \times \frac{4}{91} = \frac{20 \times 4}{51 \times 91}$ [ $∵$ Product of rational numbers = $\frac{P r o d u c t o f n u m e r a t o r s}{P r o d u c t o f d e n o m i n a t o r s}$ ]
$= \frac{80}{4641}$
Hence, the reciprocal of $\frac{80}{4641}$ is $\frac{4641}{80}$

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Negatives and Reciprocals

Standard VII Mathematics

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