Question

Question 11 (ii)
In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that:

(ii) ar(AEDF) = ar(ABCDE)

Answer 1

It can be observed that,
Area(ΔACB)=Area(ΔACF)
Then, Area(ΔACB)+Area(ACDE)=Area(ACF)+Area(ACDE)
[Adding Area(ACDE) on both sides]
⇒ Area(ABCDE) = Area(AEDF)