Question

Question 117 (ii)

Physical Science Application
Unequal masses will not balance on a fulcrum, if they are at equal distance from it, one side will go up and the other side will go down.
Unequal masses will balance when the following proportion is true.

Two children can be balanced on a see-saw, when $\frac{mass1}{length2}=\frac{mass2}{length1}$

The child on the left and child on the right are balanced. What is the mass of the child on the right?

Answer 1

It is given that, for balancing. $\frac{Mass1}{Length2}=\frac{Mass2}{Length1}$
According to the question,
Mass = 1 = 24 kg, length 1 = 3 m and length 2 = 2m
$\therefore \frac{24}{2}=\frac{Mass2}{3}[bycross-multiplication]\Rightarrow Mass2=\frac{24\times 3}{2}=36kg$