Question 2 iii 1500 families with 2 children were selected randomly- and the following data were recorded-begin array - c - c - c - c -WhineNumber of families-475-814-211111hline e n d a r r a y Compute the probability of a family- chosen at random- having no girl

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Standard VII

Mathematics

Experimental/ Empirical Probability

Question 2 ii...

Question

Question 2 (iii)
1500 families with 2 children were selected randomly, and the following data were recorded:
$\begin{matrix} N u m b e r o f g i r l s i n a f a m i l y & 2 & 1 & 0 N u m b e r o f f a m i l i e s & 475 & 814 & 211 \end{matrix}$
Compute the probability of a family, chosen at random, having no girl

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Solution

Total number of families = 475 +814 + 211= 1500
(iii) Number of families having no girl= 211
$P_{3} (a r a n d o m l y c h o s e n f a m i l y h a s n o g i r l) = \frac{N u m b e r f a m i l i e s h a v i n g n o g i r l}{T o t a l n u m b e r o f f a m i l i e s}$
$P_{3} (a r a n d o m l y c h o s e n f a m i l y h a s n o g i r l) = \frac{211}{1500}$

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Question 2 (iii)
1500 families with 2 children were selected randomly, and the following data were recorded:
$\begin{matrix} Number of girls in a family & 2 & 1 & 0 Number of families & 475 & 814 & 211 \end{matrix}$
Compute the probability of a family, chosen at random, having no girl

Q. Question 2 (i)
1500 families with 2 children were selected randomly, and the following data was recorded:

\begin{matrix} N u m b e r o f g i r l s i n a f a m i l y & 2 & 1 & 0 N u m b e r o f f a m i l i e s & 475 & 814 & 211 \end{matrix}

Compute the probability of a family,chosen at random ,having 2 girls.

1500 families with 2 children were selected randomly, and the following data were recorded:

$\begin{matrix} Number of girls in a family & 2 & 1 & 0 Number of families & 300 & 500 & 700 \end{matrix}$

Compute the probability of a family chosen at random having 2 girls.

1500 families with 2 children were selected randomly, and the following data were recorded:

Number of girls in a family	2	1	0
Number of families	475	814	211

Compute the probability of a family, chosen at random, having

(i) 2 girls (ii) 1 girl (iii) No girl

Also check whether the sum of these probabilities is 1.

1500

families with

2

children were selected randomly, and the following data were recorded:

No. of girls in a family	$2$	$1$	$0$
No. of families	$475$	$814$	$211$

Compute the probability of a family, chosen at random, having
(i)

2

girls
(ii)

1

girl
(iii) No girl
Also check whether the sum of these probabilities is

1

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Question 2 (iii) 1500 families with 2 children were selected randomly, and the following data were recorded: Number of girls in a family210Number of families475814211 Compute the probability of a family, chosen at random, having no girl

Total number of families = 475 +814 + 211= 1500 (iii) Number of families having no girl= 211 P3(a randomly chosen family has no girl)=Number families having no girlTotal number of families P3(a randomly chosen family has no girl)=2111500