Question

# Question 2 (iii) E and F are points on the sides PQ and PR respectively of a ΔPQR. For the following case, state whether EF || QR. (iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.63 cm

Solution

## In ΔPQR, E and F are two points on the sides PQ and PR respectively.  (iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm, PF = 0.36 cm (Given) Here, EQ = PQ - PE = 1.28 - 0.18 = 1.10 cm; FR = PR - PF = 2.56 - 0.36 = 2.20 cm So, PEEQ=0.181.10=18110=955...(i) And, PEFR=0.362.20 = 36220=955...(ii) ∴PEEQ=PFFR. Hence, EF is parallel to QR. MathematicsNCERT TextbookStandard X

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