You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Trapezium

PQ=1.28cm, PR...

Question

$P Q = 1.28 c m, P R = 2.56 c m, P E = 0.18 c m$ and $P F = 0.36 c m$

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Ambiguos

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Can't say

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
Given PQ=1.28 cm,PR=2.56 cm,PE=0.18 cm and PF=0.36 cm where E and F are points on PQ and PR respectively.
Now, $\frac{P E}{P Q} = \frac{0.18}{1.28} = \frac{9}{64}$
$\frac{P F}{P R} = \frac{0.36}{2.56} = \frac{9}{64}$
thus, $\frac{P E}{P Q} = \frac{P F}{P R}$
By converse of equal Intercept theorem, $E F ∥ Q R$

Suggest Corrections

Similar questions

E

and

F

are points on the sides

P Q

and

P R

respectively of a

△ P Q R

. For each of the following cases, state whether

E F ∥ Q R

P Q = 1.28 c m, P R = 2.56 c m, P E = 0.18 c m

and

P F = 0.36 c m

Question 2 (iii)
E and F are points on the sides PQ and PR respectively of a $Δ P Q R$ . For the following case, state whether EF || QR.
(iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.63 cm

E and F are points on the sides PQ and PR respectively of a ΔPQR. For each of the following cases, state whether EF || QR.

(i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm

(ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm

(iii)PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.63 cm

E

and

F

are points on the sides

P Q

and

P R

respectively of a

Δ P Q R

. For each of the following cases state whether

E F ∥ Q R

(1)

P E = 3.9 c m, E Q = 3 c m, P F = 3.6 c m a n d F R = 2.4

(2)

P E = 4 c m, Q E = 4.5 c m, P F = 8 c m a n d R F = 9 c m

(3)

P Q = 1.28 c m PR = 2.56 c m, P E = 0.18 c m a n d P F = 0.36 c m

M and N are points on the sides PQ and PR respectively of a $Δ P Q R$ . For each of the following cases, whether MN || QR:
(i) PM = 4 cm, QM = 4.5 cm, PN = 4 cm, NR = 4.5 cm
(ii) PQ =1.28 cm, PR = 2.56 cm, PM = 0.16 cm, PN = 0.32 cm

Join BYJU'S Learning Program

PQ=1.28cm,PR=2.56cm,PE=0.18cm and PF=0.36cm

The correct option is A TrueGiven PQ=1.28 cm,PR=2.56 cm,PE=0.18 cm and PF=0.36 cm where E and F are points on PQ and PR respectively.Now, PEPQ=0.181.28=964PFPR=0.362.56=964thus, PEPQ=PFPRBy converse of equal Intercept theorem, EF∥QR

$P Q = 1.28 c m, P R = 2.56 c m, P E = 0.18 c m$ and $P F = 0.36 c m$