Question

I	II
$N{H}_3$	$P{H}_3$

The bond angle in $N{H}_3$ is larger than, in $P{H}_3$ because the $P-H$ bonds are longer and the lower electronegativity of P permits electron-density to be displaced towards hydrogen to a greater extent than in the case of $N{H}_3$. Both of these effects diminish the repulsion due to bond-pairs.
If true enter 1, else enter 0.

Answer 1

Greater is the repulsion between bond pair and bond pair, greater is the bond angle.
The bond angle in $N{H}_3$ is larger than, in $P{H}_3$ because the $P-H$ bonds are longer and the lower electronegativity of P permits electron-density to be displaced towards hydrogen to a greater extent than in the case of $N{H}_3$. Both of these effects diminish the repulsion due to bond-pairs.
The given statement is true. Hence, the answer is 1.