Imagine a geostationary satellite of earth which is used as an inter continental telecast station. At what height will it have to be established?

10^{3} m

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6.4 \times 10^{3} m

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35.94 \times 10^{6} m

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at infinity

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Solution

The correct option is A at $35.94 \times 10^{6} m$
Time period for a geostationary satellite is 24 hour, so $t = 24$
And $t = 2 π \sqrt{\frac{(R + h)^{2}}{G M}}$
So, $h = 35.94 \times 10^{6} m$

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Imagine a geostationary satellite of earth which is used as an inter continental telecast station. At what height will it have to be established?

The correct option is A at 35.94×106mTime period for a geostationary satellite is 24 hour, so t=24And t=2π√(R+h)2GMSo, h=35.94×106m

The correct option is A at $35.94 \times 10^{6} m$
Time period for a geostationary satellite is 24 hour, so $t = 24$
And $t = 2 π \sqrt{\frac{(R + h)^{2}}{G M}}$
So, $h = 35.94 \times 10^{6} m$