Question

In a $3$-digit number, the ten's digit is equal to the unit digit and hundred's digit is thrice to the unit's digit. If the sum of its all three digits is $15$. Find the reversed number.

• A. $933$
• B. $339$
• C. $379$
• D. $993$

Answer 1

Answer: (B)

$339$

Let the number be $abc$ i.e., $100a+10b+c$
Where unit digit $=c$, ten's digit $=b$ and hundred's digit $=a$.
Given $b=c$ and $a=3c$
$a+b+c=15$---(1)
Substitute the values of $b$ and a in equation (1), we get
$3c+c+c=15$
$5c=15$ (Divide both the sides by $10$)
$c=3$
Therefore, $b=c=3$
$a=3c=3\times 3=9$
Hence, the required $3$-digit number is $933$.
So, the reversed number is $339$.