CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a 4-digit number 2 digits are repeated, not consecutively. If the value of 5 at the hundreds place is subtracted from the value of the digit at the thousands place, the result is 6,500. Determine the number. (More than one correct answer)

A
Seven thousand five hundred fifty-seven
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Seven thousand five hundred seventy-five
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
7,575
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
7,557
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 7,575
Detailed step-by-step solution:
1. The number is a 4-digit number. (WB1)
2. In a 4-digit number 2 digits are repeated, not consecutively.
3. The value of 5 at the hundreds place in the number will be 5×100=500.(WB1)
4. This 500 is subtracted from the value of the digit at the thousands place and gives 6,500.
5. The value at the thousands place should be 500 + 6,500 = 7,000. (WB3)
6. So the digit at the thousands place is 7 and our other digit is 5.
7. Let us form the 4-digit number in which 5 and 7 will not repeat consecutively. (WB4)
8. The only way in which 5 and 7 will not repeat consecutively is 7,575.
9. The word form of 7,575 is seven thousand five hundred seventy-five. (WB5)
10. Options A and D are correct.

WB:

Q: Why have we not selected 7,755 and 7,557?

A: For the numbers 7,755 and 7,557, at least one digit is repeated.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sambhaji Maharaj
HISTORY
Watch in App
Join BYJU'S Learning Program
CrossIcon