In a 50mL solution of H2O2 an excess of KI and dilute H2SO4 were added. The I2 liberated required 20mL of 0.1NNa2S2O3 for complete reaction. Calculate the strength of H2O2 in grams per litre.
A
0.25gL−1
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B
0.34gL−1
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C
0.68gL−1
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D
0.8gL−1
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Solution
The correct option is C0.68gL−1 2KI(aq)+H2SO4(aq)+H2O2(aq)→K2SO4(aq)+2H2O(l)+I2(g) I2(aq)+2Na2S2O3(aq)→Na2S4O6(aq)+2NaI(aq)
meq. of H2O2 in 50 ml=meq. of I2=meq. of Na2S2O3
meq. of H2O2 in 50 ml=0.1×20=2
meq. of H2O2 in 1000 ml=250×1000=40 Equivalents per litre=401000=0.04 Since, eq. weight of H2O2=342=17∴Concentration of H2O2 in grams per litre =Equivalents per litre×eq. weight of H2O2