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Question

In a 50 mL solution of H2O2 an excess of KI and dilute H2SO4 were added. The I2 liberated required 20 mL of 0.1N Na2S2O3 for complete reaction.
Calculate the strength of H2O2 in grams per litre.

A
0.25 g L1
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B
0.34 g L1
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C
0.68 g L1
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D
0.8 g L1
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Solution

The correct option is C 0.68 g L1
2KI (aq)+H2SO4 (aq)+H2O2 (aq)K2SO4 (aq)+2H2O (l)+I2 (g)
I2(aq)+2Na2S2O3(aq)Na2S4O6(aq)+2NaI(aq)

meq. of H2O2 in 50 ml=meq. of I2=meq. of Na2S2O3

meq. of H2O2 in 50 ml=0.1×20=2

meq. of H2O2 in 1000 ml=250×1000=40
Equivalents per litre=401000=0.04
Since, eq. weight of H2O2=342=17Concentration of H2O2 in grams per litre =Equivalents per litre×eq. weight of H2O2

Concentration of H2O2=0.04×17 g L1 =0.68 g L1

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