In a 68nm long DNA molecule, Adenine constitutes 25%. How many hydrogen bonds would be present between the strands? (Average length of a nucleotide is 3.4 Angstroms)
A
250
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
350
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
500
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A250
As the average length of a nucleotide is 3.4 Angstrom hence there are 200 nucleotides present in 68 nm long DNA. 2 nucleotides form a base pair hence 100 base pairs are present. Adenine-Thymine forms a base pair with a double hydrogen bond and Guanine-Cytosine form base pair with a triple bond.
According to the question, 25% of this DNA molecule consists of Adenine which means that equal percent of Thymine is present as well forming 50% DNA as Adenine-Thymine base pair ( 50 base pairs) While Rest of the 50% DNA consists of Guanine -Cytosine ( 50 base pairs ).
Based on this number of hydrogen bonds present are -