In a A-C- circuit- V and I are given by V -100 sin 100 t volt- I -100 sin100 t -3 A then the power dissipated in the circuit isA- 10 WB- 2500 WC- 104 WD- 5 W

The correct option is B 2500 W Then, E_r.m.s = E_0/√(2) and I_r.m.s = I_0/√(2) . Power dissipated P = E_r.m.s I_r.m.s cos ϕ =100/√(2)×100/√(2)× cos π/3 = 2500 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

RMS Value

In a A.C. cir...

Question

In a A.C. circuit, V and I are given by V = 100sin (100t) volt, I = 100 sin $(100 t + \frac{π}{3})$ A then the power dissipated in the circuit is

$10^{4} W$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2500 W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
2500 W

Then, $E_{r . m . s} = \frac{E_{0}}{\sqrt{2}}$ and $I_{r . m . s} = \frac{I_{0}}{\sqrt{2}}$ . Power dissipated $P = E_{r . m . s I_{r . m . s}} c o s ϕ = \frac{100}{\sqrt{2}} \times \frac{100}{\sqrt{2}} \times c o s \frac{π}{3} = 2500 W$

Suggest Corrections

Similar questions

Q. In an AC circuit

V

and

I

are given by

V = 100 sin (100 t)

volt,

I = 100 sin (100 t + \frac{π}{3})

amp the power dissipated in the circuit is

The voltage and the current of an $a . c$ circuit are $V = 100 sin (100 t)$ volt and $i = 100 sin (100 t + π / 3) m A$ receptively. The power dissipated in the circuit is:

Q. In LCR series circuit, an alternating e.m.f. 'e' and current 'i' are given by the equations

e = 100 sin (100 t)

volt,

i = 100 sin (100 t + \frac{π}{3}) m A

. The average power dissipated in the circuit will be.

Q. In an AC circuit, the potential difference

V

and current

I

are given respectively by

V = 100 sin (100 t) V

and

I = 100 sin (100 t + \frac{π}{3}) m A

The power dissipated in the circuit will be

Q. The current and voltage functions in an AC circuit are

i = 100 sin 100 t m A

V = 100 sin (100 t + \frac{π}{3}) V

The power dissipated in the circuit is

Join BYJU'S Learning Program

In a A.C. circuit, V and I are given by V = 100sin (100t) volt, I = 100 sin (100t+π3) A then the power dissipated in the circuit is

The correct option is C 2500 W Then, Er.m.s=E0√2 and Ir.m.s=I0√2 . Power dissipated P=Er.m.s Ir.m.s cos ϕ=100√2×100√2×cos π3=2500 W

In a A.C. circuit, V and I are given by V = 100sin (100t) volt, I = 100 sin $(100 t + \frac{π}{3})$ A then the power dissipated in the circuit is

The correct option is C
2500 W

Then, $E_{r . m . s} = \frac{E_{0}}{\sqrt{2}}$ and $I_{r . m . s} = \frac{I_{0}}{\sqrt{2}}$ . Power dissipated $P = E_{r . m . s I_{r . m . s}} c o s ϕ = \frac{100}{\sqrt{2}} \times \frac{100}{\sqrt{2}} \times c o s \frac{π}{3} = 2500 W$