Question

In a ∆ABC, If ∠A = 65°, ∠B = 45°, find ∠C.

Figure

Answer 1

$\begin{array}{l}\text{In}\Delta \text{ABC,}\angle \text{A+}\angle \text{B+}\angle {\text{C=180}}^0\\ {\text{=>65}}^0+{45}^0+\angle \text{C}={180}^0\\ \text{=>}\angle {\text{C=180}}^0-{110}^0={90}^0\end{array}$