Question

In a balanced Wheatstone bridge,
P= (10$\Omega$+2$\Omega$ in series) Q=x, R=(2$\Omega$+ 4$\Omega$ in series) and S=(1$\Omega$ +1$\Omega$ in series) then x =

• A. 1$\Omega$
• B. 2$\Omega$
• C. 4$\Omega$
• D. 6$\Omega$

Answer 1

Answer: (C)

4$\Omega$

for Wheatstone bridge
$\frac{P}{Q}=\frac{R}{S}$
$\frac{12}{x}=\frac{6}{2}$
$\Rightarrow x=4$
$\Rightarrow x=4\Omega$