In a camp $95 k g$ food is sufficient from $5$ percent. Find the quantity of food required for $23$ persons.

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Solution

For $5$ persons, food required $= 95$ kg

For $1$ person, food required $= \frac{95}{5} = 19$ kg

For $23$ persons, food required $= 19 \times 23$
$= 437$ kg.

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In a camp 95kg food is sufficient from 5 percent. Find the quantity of food required for 23 persons.

For 5 persons, food required =95 kgFor 1 person, food required =955=19 kgFor 23 persons, food required=19×23 =437 kg.

In a camp $95 k g$ food is sufficient from $5$ percent. Find the quantity of food required for $23$ persons.

For $5$ persons, food required $= 95$ kg

For $1$ person, food required $= \frac{95}{5} = 19$ kg

For $23$ persons, food required $= 19 \times 23$
$= 437$ kg.