Question

In a cell , the following reaction takes place:

$Fe\left(s\right)+CuS{O}_4\left(aq\right)\to FeS{O}_4\left(aq\right)+Cu\left(s\right)$

The correct cell representation is:

• A. $C{u}^{2+}\left(aq\right)|Cu\left(s\right)||Fe\left(s\right)|F{e}^{2+}\left(aq\right)$
• B. $C{u}^{2+}\left(aq\right)|Cu\left(s\right)||F{e}^{2+}\left(aq\right)|Fe\left(s\right)$
• C. $Fe\left(s\right)|F{e}^{2+}\left(aq\right)||C{u}^{2+}\left(aq\right)|Cu\left(s\right)$
• D. $Cu\left(s\right)|C{u}^{2+}\left(aq\right)||Fe\left(s\right)|F{e}^{2+}\left(aq\right)$

Answer 1

The correct option is C $Fe\left(s\right)|F{e}^{2+}\left(aq\right)||C{u}^{2+}\left(aq\right)|Cu\left(s\right)$

Since in the given reaction:

$Fe\left(s\right)$ is getiing oxidised to $F{e}^{2+}\left(aq\right)$
So, it is at anode, and must be represented at left side during cell representation.
Also,
$C{u}^{2+}\left(aq\right)$is getiing reduced to $Cu\left(s\right)$
So, it is at cathode , and must be represented at right side during cell representation.
Both representations are seperated by $||$ which indicates a salt bridge.
The correct cell representation is :
$Fe\left(s\right)|F{e}^{2+}\left(aq\right)||C{u}^{2+}\left(aq\right)|Cu\left(s\right)$