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Byju's Answer
Standard XII
Chemistry
Reactivity with Halogens and Hydrogen (Group 2)
In a cell, th...
Question
In a cell, the following reactions take place
F
e
2
+
→
F
e
3
+
+
e
−
E
∘
F
e
3
+
/
F
e
2
+
=
0.77
V
2
I
−
→
I
2
+
2
e
−
E
∘
I
2
/
I
−
=
0.54
V
The standard electrode potential for the spontaneous reaction in the cell is
x
×
10
–
2
V
at 208 K. The value of
x
is
(Nearest Integer)
Open in App
Solution
F
e
2
+
→
F
e
3
+
+
e
−
E
∘
F
e
3
+
/
F
e
2
+
=
0.77
V
2
I
−
→
I
2
+
2
e
−
E
∘
I
2
/
I
−
=
0.54
V
The cell reaction is,
2
F
e
2
+
+
I
2
→
2
F
e
3
+
+
2
I
−
E
∘
c
e
l
l
=
E
∘
c
a
t
h
o
d
e
−
E
∘
a
n
o
d
e
=
0.77
–
0.54
=
0.23
V
=
23
×
10
–
2
V
Suggest Corrections
18
Similar questions
Q.
For the reaction,
F
e
3
+
+
3
e
⇌
F
e
,
E
o
is -0.036 V and the standard electrode potential(SEP) for
F
e
3
+
+
e
⇌
F
e
2
+
is 0.77 V.
Hence,
E
o
for
F
e
2
+
+
2
e
⇌
F
e
is:
Q.
Given, standard electrode potentials,
F
e
2
+
+
2
e
−
→
F
e
,
E
o
=
−
0.440
V
F
e
3
+
+
3
e
−
→
F
e
,
E
o
=
−
0.036
V
The standard electrode potential
(
E
o
)
for
F
e
3
+
+
e
−
→
F
e
2
+
is:
Q.
The standard reduction potentials for the following reactions are:
F
e
3
+
+
3
e
−
→
F
e
with
E
∘
=
−
0.036
V
F
e
2
+
+
2
e
−
→
F
e
with
E
∘
=
−
0.44
V
What would be the standard electrode potential for the reaction
F
e
3
+
+
e
−
→
F
e
2
+
?
Q.
Given standard electrode potentials,
F
e
2
+
2
e
−
→
F
e
,
E
∘
=
−
0.440
V
F
e
3
+
+
3
e
−
→
F
e
,
E
∘
=
−
0.036
V
The standard electrode potential
(
E
∘
)
for
F
e
3
+
+
e
−
→
F
e
2
+
is:
Q.
For the reaction,
F
e
3
+
+
3
e
−
⇌
F
e
,
E
∘
is
−
0.036
v
o
l
t
and the standard electrode potential for
F
e
3
+
+
e
−
⇌
F
e
2
+
is
0.771
v
o
l
t
. Calculate the
E
∘
for
F
e
2
+
+
2
e
−
⇌
F
e
.
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