Question

In a certain process, 525 J of heat is absorbed by a system while 269 J of work is done on the system. What is the change in the internal energy for the process?

• A. 256 J
• B. 794 J
• C. 510 J
• D. 300 J

Answer 1

The correct option is B 794 J

$\Delta Q=+525J,\Delta W=+269J$
From the 1st law of thermodynamics,
$\Delta U=(\Delta Q+\Delta W)=(525+269)J=794J$