1
Question
In
a process, 701 J of heat is absorbed by a system and 394 J of
work is done by the system. What is the change in internal energy for
the process?
In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?
Open in App
Solution
According
to the first
law of thermodynamics,
ΔU
= q
+ W (i)
Where,
ΔU
= change in internal energy for a process
q
= heat
W
= work
Given,
q
= + 701 J (Since heat is absorbed)
W
= –394 J (Since work is done by the system)
Substituting
the values in expression (i), we get
ΔU
= 701 J + (–394 J)
ΔU
= 307 J
Hence,
the change in internal energy for the given process is 307 J.
According to the first law of thermodynamics,
ΔU = q + W (i)
Where,
ΔU = change in internal energy for a process
q = heat
W = work
Given,
q = + 701 J (Since heat is absorbed)
W = –394 J (Since work is done by the system)
Substituting the values in expression (i), we get
ΔU = 701 J + (–394 J)
ΔU = 307 J
Hence, the change in internal energy for the given process is 307 J.
Suggest Corrections
1
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
