Question

In a chemical equilibrium $A+B\rightleftharpoons C+D$ when one mole each of the two reactants are mixed, $0.4mole$ each of the products are formed.The equilibrium constant calculated is :-

• A. $1$
• B. $0.36$
• C. $2.25$
• D. $\frac{4}{9}$

Answer 1

The correct option is D $\frac{4}{9}$

$\underset{1(1-x)}{A}+\underset{1(1-x)}{B}\rightleftharpoons \underset{0x}{C}+\underset{0x}{D}$

$K=\frac{\left[C\right]\left[D\right]}{\left[A\right]\left[B\right]}=\frac{x\times x}{(1-x)(1-x)}$

A/Q

$x=0.4$

Hence, $K=\frac{{0.4}^2}{{0.6}^2}=\frac{4}{9}$

Hence, option D is correct