Question

In a chemical equilibrium $A+B\rightleftharpoons C+D$ when one mole each of the two reactants are mixed, 0.4 mol each of the products is formed. The equilibrium constant is:

• A. $1$
• B. $0.36$
• C. $2.25$
• D. $\frac{4}{9}$

Answer 1

Answer: (D)

$\frac{4}{9}$

$A+B\rightleftharpoons C+D$

At eqm. $(1-0.4)(1-0.4)0.40.4$

$K_c=\frac{\left(0.4\right)\left(0.4\right)}{\left(0.6\right)\left(0.6\right)}$

$\frac{4^2}{36}=\frac{16}{36}=\frac{4}{9}$

D is correct answer.