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Question
In a chemical reaction ∆H = 150 kj and ∆S = 100j/k at 300 K. Therefore ∆G will be:
In a chemical reaction ∆H = 150 kj and ∆S = 100j/k at 300 K. Therefore ∆G will be:
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Solution
The correct option is B 120 kJ
∆ G = ∆H - T∆S
= 150 – 300 × 100
= 120 kj
120 kJ
∆ G = ∆H - T∆S
= 150 – 300 × 100
= 120 kj
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