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Question

In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.

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Solution

Diameter of the circle =40 cm
Radius (r) of the circle =402=20 cm
Let AB be a chord (length = 20 cm) of the circle.
In OAB, OA = OB = Radius of circle = 20 cm
Also, AB = 20 cm
Thus, OAB is an equilateral triangle.
θ=60=π3 radian
We know that in a circle of radius r unit, if an arc of length I unit subtends an angle θ radian at the centre, then θ=lr
π3=arc AB20arc AB=203π cm
408006_429773_ans_582cb164f7514e4c993c90745fdc9648.png

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