Two parallel chords are drawn in a circle of diameter 30.0 cm. The length of one chord is 24.0 cm and the distance between the two chords is 21.0 cm. find the length of the other chord.

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Solution

First chord $= 24$ cm
Second chord $= x$ cm
Radius $= D / 2 = 15$ cm
Pythagorean theorem
$(12)^{2} +$ [half of second chord] $^{2} = 15^{2}$
$[d]^{2} = 15^{2} - 12^{2} = 81$
$d = 9$ .

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Two parallel chords are drawn in a circle of diameter 30.0 cm. The length of one chord is 24.0 cm and the distance between the two chords is 21.0 cm. find the length of the other chord.

First chord =24cmSecond chord=xcmRadius =D/2=15cmPythagorean theorem(12)2+[half of second chord]2=152[d]2=152−122=81d=9.

First chord $= 24$ cm
Second chord $= x$ cm
Radius $= D / 2 = 15$ cm
Pythagorean theorem
$(12)^{2} +$ [half of second chord] $^{2} = 15^{2}$
$[d]^{2} = 15^{2} - 12^{2} = 81$
$d = 9$ .