In a circle of radius 7 cm, tangent PT is drawn from a point P such that PT = 24cm. If O is the centre of the circle. then length OP = ?

(a) 30 cm (b) 28 cm (c) 25 (d) 18 cm

Open in App

Solution

$O P^{2} = O T^{2} + T P^{2}$
$O P^{2} = 7^{2} + 24^{2}$
$O P^{2} = 49 + 576$
$O P^{2} = 625$
OP=25

Suggest Corrections

Similar questions

Q. In a circle of radius 7 cm, tangent PT is drawn from a point P, such that PT = 24 cm. If O is the centre of the circle, then OP = ?
Figure

(a) 30 cm
(b) 28 cm
(c) 25 cm
(d) 31 cm

Q. A point P is

26 c m

away from the centre O of a circle and the length PT of tangent drawn from P to the circle is

10 c m

. Then the radius of the circle is

In the given figure, point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 24 cm. Then the radius of the circle is

(a) 10 cm (b) 12 cm (c) 13 cm (d) 15 cm

Q. Let C be a circle centre O. Let T be a point on the circle and P a point outside the circle such that PT is tangent to C. Assume that the segment OP intersects C in a point Q If PT = 12 and PQ = 8 the radius of C is

If two tangents PT and PS are drawn to a circle with centre O and radius 'r' from an external point P and OP=2r then

∠

TOP is ____.

Join BYJU'S Learning Program

In a circle of radius 7 cm, tangent PT is drawn from a point P such that PT = 24cm. If O is the centre of the circle. then length OP = ? (a) 30 cm (b) 28 cm (c) 25 (d) 18 cm

OP2=OT2+TP2 OP2=72+242 OP2=49+576 OP2=625 OP=25

In a circle of radius 7 cm, tangent PT is drawn from a point P such that PT = 24cm. If O is the centre of the circle. then length OP = ?

(a) 30 cm (b) 28 cm (c) 25 (d) 18 cm

$O P^{2} = O T^{2} + T P^{2}$
$O P^{2} = 7^{2} + 24^{2}$
$O P^{2} = 49 + 576$
$O P^{2} = 625$
OP=25