In a circuit shown, the average power dissipated in the resistor is (assume diode to be ideal)

\frac{E_{0}^{2}}{2 R}

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\frac{E_{0}^{2}}{4 R}

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\frac{E_{0}^{2}}{R}

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Zero

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Solution

The correct option is D Zero
Average value of $A C$ $($ sinusoidal $)$ for complete cycle is zero
So $,$ $E_{a v g} = 0$
So $,$ power $= 0$
Hence,
option $(D)$ is correct answer.

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In a circuit shown, the average power dissipated in the resistor is (assume diode to be ideal)

The correct option is D ZeroAverage value of AC (sinusoidal) for complete cycle is zeroSo, Eavg=0So, power=0 Hence,option (D) is correct answer.

The correct option is D Zero
Average value of $A C$ $($ sinusoidal $)$ for complete cycle is zero
So $,$ $E_{a v g} = 0$
So $,$ power $= 0$
Hence,
option $(D)$ is correct answer.