Question

In the circuit shown, the average power dissipated in the resistor is (assume diode to be ideal)

• A. $\frac{E_0^2}{2R}$
• B. $\frac{E_0^2}{4R}$
• C. $\frac{E_0^2}{R}$
• D. Zero

Answer 1

The correct option is B $\frac{E_0^2}{4R}$

R.E.F image

graph of current with diode

graph of current with diode

hence power dissipated with diode $=\frac{1}{2}$ (Power dissipated without diode)

$=\frac{1}{2}\left(\frac{{\left(\frac{E_0}{\sqrt{2}}\right)}^2}{R}\right)$

$=\frac{1}{4}\frac{E_0^2}{R}$