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Byju's Answer
Standard XII
Physics
Alternating Current Applied to an Inductor
In a circuit,...
Question
In a circuit, the frequency is
f
=
1000
2
π
Hz and the inductance is 2 henry, then the reactance will be
A
200
Ω
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B
200
μ
Ω
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C
2000
Ω
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D
2000
μ
Ω
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Solution
The correct option is
B
2000
Ω
Given :
f
=
1000
2
π
L
=
2
H
Thus
w
=
2
π
f
=
2
π
×
1000
2
π
=
1000
Reactance
X
L
=
ω
L
X
L
=
1000
×
2
=
2000
Ω
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0
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