In a city $20 %$ of the population travels by car, $50 %$ travels by bus and $10 %$ travels by both car and bus. Then, persons travelling by car or bus is

80 %

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40 %

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60 %

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70 %

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Solution

The correct option is C $60 %$
Suppose C and B represents the population travel by car & bus respectively.
$n (C U B) = n (C) + n (B) - n (B \cap C) = 0.20 + 0.50 - 0.10 = 0.6 o r 60 %$
Option C is the correct answer.

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In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then, persons travelling by car or bus is

The correct option is C 60%Suppose C and B represents the population travel by car & bus respectively.n(CUB)=n(C)+n(B)−n(B∩C)=0.20+0.50−0.10=0.6or60%Option C is the correct answer.

In a city $20 %$ of the population travels by car, $50 %$ travels by bus and $10 %$ travels by both car and bus. Then, persons travelling by car or bus is

The correct option is C $60 %$
Suppose C and B represents the population travel by car & bus respectively.
$n (C U B) = n (C) + n (B) - n (B \cap C) = 0.20 + 0.50 - 0.10 = 0.6 o r 60 %$
Option C is the correct answer.