In a city $20$ percent of the population travels by car, $50$ percent travels by bus and $10$ percent travels by both car and bus. Then the percentage of population travelling by car or bus is

$80$ percent

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$40$ percent

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$60$ percent

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$70$ percent

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Solution

The correct option is C
$60$ percent

Let $C and B$ represent the population travelling by a car and bus respectively.
From the given information, we have
$n (C) = 20, n (B) = 50, n (C \cap B) = 10$

Using $n (C \cup B) = n (C) + n (B) - n (C \cap B)$
$= 20 + 50 - 10$
$= 60$ .

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In a city 20 percent of the population travels by car, 50 percent travels by bus and 10 percent travels by both car and bus. Then the percentage of population travelling by car or bus is

The correct option is C 60 percent Let C and B represent the population travelling by a car and bus respectively. From the given information, we have n(C)=20,n(B)=50,n(C∩B)=10 Using n(C∪B)=n(C)+n(B)−n(C∩B) =20+50−10 =60.

In a city $20$ percent of the population travels by car, $50$ percent travels by bus and $10$ percent travels by both car and bus. Then the percentage of population travelling by car or bus is

The correct option is C
$60$ percent

Let $C and B$ represent the population travelling by a car and bus respectively.
From the given information, we have
$n (C) = 20, n (B) = 50, n (C \cap B) = 10$

Using $n (C \cup B) = n (C) + n (B) - n (C \cap B)$
$= 20 + 50 - 10$
$= 60$ .