Question

In a college, $\frac{5}{9^{th}}$ of the students are boys and the remaining are girls. On a particular day, $\frac{4}{5^{th}}$ of the boys and $\frac{7}{8^{th}}$ of the girls were absent. How many more boys were absent than the girls, if total number of boys is 80 more than the number of girls?

• A. 6
• B. 75
• C. 45
• D. 40

Answer 1

The correct option is D

40

$\frac{1}{9^{th}}$ of total students = 80 total students = 720

Boys = 400, girls = 320.

Boys absent =

$\frac{4}{5}$ $\times$ 400 = 320;

Girls absent =

$\frac{7}{8}$ $\times$ 320 = 280

Difference = 320 – 280 = 40.