Question

In a constant volume gas thermometer the pressure of the working gas is measured by the difference in the level of mercury in the two arms of a U-tube connect to the gas at one end. When the bulb is placed at the room temperature ${27.0}^{\circ }$, the mercury column in the arm open to atmosphere stands 5.00 cm above the level of mercury in the other arm. When the bulb is placed in a hot liquid, the difference of mercury levels becomes 45.0 cm. Calculate the temperature(x+170)(${}^{o}C$) of the liquid. Mark the value of x.(Atmospheric pressure = 75.0 cm of mercury.)

Answer 1

$\frac{P_2}{P_1}=\frac{273+T}{273+27}=\frac{75+45}{75+5}⟹T={177}^{0}C$