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Dalton's Law of Partial Pressures

In a containe...

Question

In a container 96g of $O_{2}$ and 335g of Ne is present. If total pressure of gaseous mixture is 25 atm. Then what will be partial pressure of Ne?

A

21.20 atm

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B

15.7 atm

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C

42.6 atm

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D

3.56 atm

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Solution

The correct option is A 21.20 atm
No. of moles of $O_{2} = \frac{96}{32} \Rightarrow$ $3$ moles
No of moles of $N e = \frac{335}{20} \Rightarrow$ $16.75$ moles
Partial pressure of a molecule = mole fraction of molecule $\times$ Total pressure
Partial pressure of $N e$
$= \frac{16.75}{3 + 16.75} \times 25$ atm
$= \frac{16.75}{19.75} \times 25$
$= 21.20$ atm

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