Question

In a copper voltmeter, mass deposited in thirty second is m g. If the time -current graph is an shown in the figure 22.25, ECE of copper is

• A. m
• B. m/2
• C. 0.1 m
• D. 0.6 m

Answer 1

The correct option is B m/2

Given : $W=m$ g

Using $W=Zit$ where $Z$ is the ECE of copper

From graph, $it=\frac{1}{2}\times [10+30]\times 100=2000$ mAs $2$ As

$⟹$ $Z=\frac{W}{it}=\frac{m}{2}$