Question

In a cricket match, a batsman hits a boundary $12$ times out of $80$ balls he plays. Further, if he plays one ball more, what will be the probability that:
(ii). He does not hit a boundary

Answer 1

Given: Batsman hits a boundary $12$ times out of $80$ balls he plays.

Total number of possible outcomes $=80$

Favorable outcomes that a batsman does not hit a boundary
$=80-12=68$

Probability that he does not hit a boundary

$=\frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

$=\frac{68}{80}$

$=\frac{17}{20}$

Hence, the probability that he does not hit a boundary is $\frac{17}{20}$.