Question

In a cricket match, a batsman hits a boundary 4 times out of the 32 balls he faces. In a given ball, what is the probability that he does not hit a boundary?
(a) $\frac{1}{8}$

(b) $\frac{7}{8}$

(c) $\frac{1}{7}$

(d) $\frac{6}{7}$

Answer 1

(b) $\frac{7}{8}$

Total number of balls that the batsman faces = 32
Number of times the batsman hits a boundary = 4
Number of times the batsman does not hit a boundary = (32 − 4 ) = 28

Let E be the event that the batsman does not hit a boundary.

∴ Required probability = P(E) = $\frac{28}{32}=\frac{7}{8}$