Question

In a cuboidal box $30\text{cm}\times 20\text{cm}\times 10\text{cm}$, how many cubes of $5\text{cm}$ length each can be arranged ?

Answer 1

We have,

Measurement of box $=30\text{cm}\times 20\text{cm}\times 10\text{cm}$

and,

Edge of cube $=5\text{cm}$

Now,

$\text{No. of cubes}$ $=\frac{\text{Volume of cuboidal box}}{\text{Volume of the cube}}$

$=\frac{l\times b\times h}{a^3}$

$=\frac{30\times 20\times 10}{5\times 5\times 5}$ (Divide $30,20$ and $10$ by $5$ we get $6,4$ and $2$ respectively)

$=6\times 4\times 2$

$=48$

Hence, total no. of cubes we get from the cubical box $=48$