Question

In a cyclic process, heat transfers are $+14.7kJ$ , $-25.2kJ$, $-3.56kJ$ and $+31.5kJ$. What is the net work done in the net cyclic process?

• A. $+10.56kJ$
• B. $-10.56kJ$
• C. $-17.44kJ$
• D. $+17.44kJ$

Answer 1

The correct option is C $-17.44kJ$

In the cyclic process, $△U_{cyc}=0$
$but,W+q=△U$
Therefore, $W_{cyc}+q_{cyc}=0...\left(1\right)$

$q_{cyc}=[14.7-25.2-3.56+31.5]kJ...\left(2\right)$

Putting (2) in (1) we get,

$W_{cyc}=-17.44kJ$