In a cyclic waste power plant for thermal decomposition of waste , hot gases are supplied from a "Kentuki Chamber" where gases are heated under Kentuki process : $P = k V T^{3}$ where P, V and T are pressure, volume and temperature of gases in chamber and k is positive constant. Work done by $5 m o l e$ of hot gases when temperature is raised from $500 K t o 550 K$ is

625 R

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- 625 R

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250 R

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- 250 R

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Solution

The correct option is D $- 250 R$
We have,
$P V = n R T$ and $W = \int P d V$
i.e., $W = n R (T_{i} - T_{f})$
= $5 \times R (500 - 550)$
= $- 250 R$

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The correct option is D −250RWe have,PV=nRT and W=∫PdVi.e., W=nR(Ti−Tf) = 5×R(500−550) = −250R

The correct option is D $- 250 R$
We have,
$P V = n R T$ and $W = \int P d V$
i.e., $W = n R (T_{i} - T_{f})$
= $5 \times R (500 - 550)$
= $- 250 R$