In a cylinder of base radius 10 cm- liquids is filled to the height of 9 cm- A metal cube of diagonal 8-3 cm is immersed completely in the liquid- Find the height by which the water will rise in the cylinder-

a√(3) = 8√(3)⇒ a = 8 Volume occupied by cube = a^3 = 512 #160; cm^3 Also 512 = π(10)^2h ⇒ h = 1.63 cm ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Surface Area of Combined Figures

In a cylinder...

Question

In a cylinder of base radius $10 c m$ , liquids is filled to the height of $9 c m$ . A metal cube of diagonal $8 \sqrt{3} c m$ is immersed completely in the liquid. Find the height by which the water will rise in the cylinder.

Open in App

Solution

$a \sqrt{3} = 8 \sqrt{3} \Rightarrow a = 8$

Volume occupied by cube $= a^{3} = 512 c m^{3}$

Also $512 = π (10)^{2} h$

$\Rightarrow h = 1.63 c m$

Suggest Corrections

Similar questions

Q. A glass cylinder with diameter

20 c m

has water to a height of

9 c m

. A metal cube of

8 c m

edge is immersed in it completely. Calculate the height by which water will rise in the cylinder. use

π = 22 / 7

Q. A glass cylinder with diameter 20 cm has water to a height of 9 cm. A metal cube of 8 cm edge is immersed in it completely. Calculate the height by which water will rise in the cylinder.

A glass cylinder with diameter 14 cm has water to a height of 7 cm. A metal cube of 8 cm edge is immersed in it completely. Calculate the height by which water will rise in the cylinder.

A sphere of radius 5 cm is immersed in water filled in a cylinder, the level of water rises $\frac{5}{3}$ cm. Find the radius of the cylinder.

A cylindrical vessel with internal diameter 10 cm and height 10.5 cm is full of water. A solid cone of base diameter 7 cm and height 6 cm is completely immersed in water. Find the volume of water (i) displaced out of the cylinder (ii) left in the cylinder.

Join BYJU'S Learning Program

In a cylinder of base radius 10 cm, liquids is filled to the height of 9 cm. A metal cube of diagonal 8√3cm is immersed completely in the liquid. Find the height by which the water will rise in the cylinder.

a√3=8√3⇒a=8Volume occupied by cube =a3=512cm3Also 512=π(10)2h⇒h=1.63cm

In a cylinder of base radius $10 c m$ , liquids is filled to the height of $9 c m$ . A metal cube of diagonal $8 \sqrt{3} c m$ is immersed completely in the liquid. Find the height by which the water will rise in the cylinder.

$a \sqrt{3} = 8 \sqrt{3} \Rightarrow a = 8$

Volume occupied by cube $= a^{3} = 512 c m^{3}$

Also $512 = π (10)^{2} h$

$\Rightarrow h = 1.63 c m$