Question

In a cylinder of cooling gas 11.2 kg butane is filled. If 1500 KJ energy is required for cooking food daily then calculate that for how many days this cylinder is sufficient for fuel; whereas enthalpy of combustion of butane is $2658kJ{mol}^{-1}$

Answer 1

Molar mass of butane $=58g/mol$

$58g$ of butane gives $2658kJ$ of heat energy.

$\therefore 11.2kg$ of butane will give heat energy $=\frac{2658}{58}\times 11200=513.27\times {10}^{3}KJ$

Daily energy required for cooking $=1500\text{kJ per day}$

$\therefore$ Number of days cylinder will last $=\frac{513.27\times {10}^3}{1500}\approx 342\text{days}$

Hence the cylinder is sufficient for $342$ days.