Question

In a cylinder their are $60g$ Ne and $64g{O}_2$. If pressure of mixture of gases in cylinder is $30$ bar then in this cylinder partial pressure (in bar) of $O_2$ is

• A. $30$
• B. $20$
• C. $15$
• D. $12$

Answer 1

Answer: (D)

$12$

Partial pressure = mole fraction times total pressure

moles of Ne $=\frac{60}{20}=3$

moles of oxygen $=\frac{64}{32}=2$

mole fraction of oxygen $=\frac{2}{5}=0.4$

partial pressure of oxygen $=0.4\times 30=12$ bar