Question

In a Δ ABC, AD bisects ∠A and ∠C > ∠B. Prove that ∠ADB > ∠ADC.

Answer 1

In the given ΔABC, AD bisects and. We need to prove.

Let,

Also,

As AD bisects,

…..(1)

Now, in ΔABD, using exterior angle theorem, we get,

Similarly,

[using (1)]

Further, it is given,

Adding to both the sides

Thus,

Hence proved.