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Question

In a triangle ABC, AC = AB and the altitude AD bisects BC. Prove that ΔADC ΔADB.

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Solution

Given: AC = AB, ADC = ADB = 90° and BD = DC

To Prove: ΔADB ΔADC

Proof:

In ΔADB and ΔADC:

AB = AC (Given)

AD = AD (Common)

BD = DC (Given)

∴ ΔADB ΔADC (SSS congruency)


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